By yusijia

Updated:

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//题目大意：
//有个人想买酒，手头上有买n瓶酒的钱，买了n瓶酒，现在酒店有促销活动，3个空瓶可以换一瓶，4个瓶盖换一瓶
//问换完后总共可以喝多少瓶酒

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#include <cstdio>
#include <cstring>
#include <cstdlib>
#include <iostream>
#include <algorithm>
using namespace std;


int main()
{
    int T;
    int a,b, n, tmp1, tmp2;
    scanf("%d", &T);
    while(T--){
        scanf("%d", &n);
        a = b = n;
        while(a / 3 != 0 || b / 4 != 0){
            n = a / 3 + b / 4 + n;
            tmp1 = a / 3;	
            tmp2 = b / 4;
            a = a / 3 + a % 3 + tmp2;//主要是这里有坑
            b = b / 4 + b % 4 + tmp1;
        }
        printf("%d\n", n);
    }
    return 0;
}
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